Resolution of Spectrum - Bandwidth
q Bandwidth (Df)= width of the frequency band è resolution of spectrum
     Df = 1/N (cycle per unit time interval)
q For example, if a time series has 900 monthly-mean data:
     bandwidth = 1/900 (cycle per month).
     Nyquist frequency = ½ (cycle per month)
     Total number of frequency bands = (0-Nyquist frequency)/bandwidth
                                                            = (0.5)/(1/900) = 450 = N/2
     Each frequency band has about 2 degree of freedom.
q If we average several bands together, we increase the degrees of freedom
but reduce the resolution (larger bandwidth).